A very good reason for this is that it makes things easier if you want to make changes that will be reflected when you return to the function that created the instance of it. If you want to change value of that character inside a function, then you must pass a pointer to it, but there's no problem in accessing it like you do: if (*val == 'I') { *val = 'S'; } It's more about what does your function expects the input to be, if it expects input to be a pointer to a single character, then it's totally fine for it to receive a char* and only access the data this pointer points to. How to pass a string to a function in C is explained in this article. It is also common to pass in the length of the string: void function(char *myString, size_t lengthMyString); P.S. You've declared an array of 7 pointers to char. Dot Plots: b.Histograms: c. BoxPlots: A Box and Whisker Plot (or Box Plot) is a convenient way of visually displaying the data distribution through their quartiles. char *ptr is the character pointer that will store the base address of the character array (string) which is going to be passed through main () function. Now what you need is just. #include void disp( int *num) { printf("%d ", *num); } int main() { int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0}; for (int i=0; i<10; i++) { /* Passing addresses of array elements*/ disp (&arr[i]); } return 0; } The strlen() accepts an argument of type pointer to char or (char*), so you can either pass a string literal or an array of characters.It returns the number of characters in the string excluding the null character '\0'. If you have a function that takes a const char * pointer, and you have a char array or char pointer, it is valid C/C++ to pass the pointer without cast. We can get the address of memory by using the function pointer. c - how passing char* to a function works? - Stack Overflow Pass char* to be initialized in function - C++ Forum There are three ways by which the values of structure can be transferred from one function to another. Multiple people have already pointed to problems in this code. , 'j' } ; function ( array ) ; } These are given as follows −. You need to change the definition of printNames to have the parameter type match what … P.S. So, we will be using that idea to pass structure pointer to a function. There are different ways in which parameter data can be passed into and out of methods and functions. In C language, there are three methods to convert a char type variable to an int. C function Pointer

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